Or use glue from flatland.useful.seq <https://github.com/flatland/useful>
 and:

user=> (glue conj [] (fn [s n] (= (inc (last s)) n)) [1 3 4 5 7 9 10 13])
([1] [3 4 5] [7] [9 10] [13])


On 19 March 2014 04:10, Shantanu Kumar <kumar.shant...@gmail.com> wrote:

>
>
> On Wednesday, 19 March 2014 09:39:56 UTC+5:30, Shantanu Kumar wrote:
>>
>> Something like this?
>>
>> (defn x [1 3 4 5 7 9 10 13])
>>
>
> Sory for the typo. Should be (def x [1 3 4 5 7 9 10 13])
>
>
>>
>> (reduce (fn [a i] (let [y (last a) z (last y)] (if (and z (= (inc z) i))
>> (conj (pop a) (conj y i)) (conj a [i])))) [] x)
>>
>> Shantanu
>>
>> On Wednesday, 19 March 2014 08:26:43 UTC+5:30, John Gabriele wrote:
>>>
>>> If you've got a sorted list of numbers, for example:
>>>
>>>     [1 3 4 5 7 9 10 13]
>>>
>>> where some are consecutive, how can you pull out the consecutive runs?
>>> That is, either produce
>>>
>>>     [1 [3 4 5] 7 [9 10] 13]    ; or maybe something like
>>>     [[1 7 13] [3 4 5] [9 10]]  ; (the first vec is the elements left
>>> over)
>>>
>>> from the original coll?
>>>
>>> I can do it in Python in an imperative style, but it's a bit messy. My
>>> hunch is that there's probably a shorter way in Clojure, but I'm not seeing
>>> it.
>>>
>>> Thanks!
>>>
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