Err, this was bugging me all day when I went afk.  I wrote it too quickly 
and am missing the case where the sub-seq starts right after seeing the 
first val, [:b :b :c].

Will fix it if I have time today, but may need to take a slightly different 
approach.  Fun problem, btw. :)

On Saturday, June 7, 2014 2:31:04 PM UTC-5, Alex Walker wrote:
>
> Here's a solution based on your description that behaves like core 
> partition fns, taking liberty to presume your example should've matched the 
> output below.
>
> (defn partition-by-seq
>   [sub-seq coll]
>   (letfn [(step [coll]
>             (when-let [coll (seq coll)]
>               (let [[run more] (split-with (partial not= (first sub-seq)) 
> coll)
>                     [possible-match more] (split-at (count sub-seq) more)]
>                 (if (= possible-match sub-seq)
>                     (if (seq run)
>                         (cons run (cons possible-match (lazy-seq (step 
> more))))
>                         (cons possible-match           (lazy-seq (step 
> more))))
>                     (cons (concat run possible-match)  (lazy-seq (step 
> more)))))))]
>     (or (step coll) ())))
>  
> => (partition-by-seq [:b :c] [])
>  
> ()
>  
> => (partition-by-seq [:b :c] [:a :d])
>  
> ((:a :d))
>  
> => (partition-by-seq [:b :c] [:a :b :c :d :a :b :c :d :a :b :c])
>  
> ((:a) (:b :c) (:d :a) (:b :c) (:d :a) (:b :c))
>
>
>
> On Tuesday, June 3, 2014 4:05:16 AM UTC-5, Ulrich Küttler wrote:
>>
>> Hi,
>>
>> what is the preferred way to find sub-seqs in a seq? I am trying to 
>> convert
>>
>> [:a :b :c :d :a :b :c :d :a :b :c]
>>
>> into
>>
>> ((:a) (:b :c) (:a :d) (:b :c) (:a))
>>
>> using the sub-seq (:b :c) instead of positions.
>>
>> partition, partition-by and the like all look at one element at a time. 
>> What I need is a search based on seqs. Are there functions that support 
>> such a search / split?
>>
>> Uli
>>
>

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