>
> Suppose at my REPL I do...
>
> (defn direct-report-oneplustwo [] (println (str "Direct one plus two is "
> ((fn [n] (+ 1 n)) 2) ".")))
>
> ...then I presume that the compiler has compiled my
> direct-report-oneplustwo function, and that this has included compilation
> of my anonymous function (fn [n] (+ 1 n)).  So that now if I run...
>
> (direct-report-oneplustwo)
>
> ...at my REPL it just needs to run this precompiled code to tell me my
> answer 3 - no additional compilation required.
>
> So far so good.
>
> But what if instead I do this at my REPL...
>
> (defn adder-make [m] (fn [n] (+ m n)))
>
> (defn indirect-report-oneplustwo [] (println (str "Indirect one plus two
> is " ((adder-make 1) 2) ".")))
>
> ...Now at this point, both adder-make and indirect-report-oneplustwo
> should have been compiled.  But unlike our first approach, the anonymous
> function (fn [n] (+ 1 n)) has not yet been created by (adder-make 1) and so
> presumably (??) has not yet been compiled??
>
> I am presuming that it is only when we actually run the report function...
>
> (indirect-report-oneplustwo)
>
> ...that (adder-make 1) is actually run, thereby producing the anonymous
> function (fn [n] (+ 1 n)), which then gets compiled right then-and-there,
> immediately followed by its execution??
>

​Well, you misunderstand it, as far as I know, clojure treat all fn as
object, so in your adder-maker example, clojure compiled two fn as object,
that's adder-maker itself and anonymous function it returns.

The compiled add-maker is just instantiate that anonymous with `m`, and
return it. So (adder-maker 1) will produce that instantiated anonymous
function, and since it's a function and it's in the first position of list,
clojure will invoke it with 2, and that anonymous function will do actual
computation.

functions are compiled at once when clojure reader meet them, and
invocation is just the matter of instantiate.

Thanks,
Di Xu

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