swap! is implemented using Java's AtomicReference class and its
compareAndSet method.  I haven't dug into the Java source code implementing
that class, but you can read the Java documentation for all Atomic* Java
classes here:

https://docs.oracle.com/javase/7/docs/api/java/util/concurrent/atomic/package-summary.html

The summary there is that all accesses to Atomic* classes should have
similar memory model guarantees as Java fields declared volatile.  I don't
have a good authoritative link handy for Java documentation on volatile,
but the basic idea is that they should not be cached locally by individual
threads, but be visible to all.

Andy


On Tue, Jun 9, 2015 at 11:33 AM, Michael Gardner <gardne...@gmail.com>
wrote:

> I'm talking about a scenario where a single thread does inc, followed
> shortly by dec. Obviously from that thread's perspective, the value will
> never be zero, but what about as seen by other threads?
>
> My understanding of Java's memory model is that instructions within a
> single thread *can* get reordered, and Java only guarantees that they will
> *appear* to have executed in order from the perspective of the executing
> thread. Other threads might see those instructions as executing
> out-of-order. What I'm wondering is whether atoms are subject to this as
> well.
>
> > On Jun 9, 2015, at 10:16 AM, Andy Fingerhut <andy.finger...@gmail.com>
> wrote:
> >
> > I am not sure why Atamert says "No".
> >
> > If the (swap! a inc) and (swap! a dec) are executed in different
> threads, and they can occur in either order because there is no
> synchronization between those threads that prevents one of the two possible
> orders from occurring, then another thread *could* see a value of 0, if and
> when the (swap! a dec) occurs first.
> >
> > If the (swap! a inc) and (swap! a dec) are executed sequentially in a
> single thread, and no other thread is modifying a, then by normal
> sequential execution the atom should change from 1 to 2, then from 2 back
> to 1.
> >
> > Andy
> >
> > On Tue, Jun 9, 2015 at 9:38 AM, Atamert Ölçgen <mu...@muhuk.com> wrote:
> >
> >
> > On Tue, Jun 9, 2015 at 7:30 PM, Michael Gardner <gardne...@gmail.com>
> wrote:
> > This might be blindingly obvious to some, but I can't find any
> discussion about it. Let's say I have code like the following:
> >
> > (def a (atom 1))
> > ...
> > (swap! a inc)
> > (swap! a dec)
> >
> > Is there any possibility of another thread seeing a=0? If not, what
> provides this guarantee?
> >
> > No. Not if those two swap! calls are made from different threads.
> >
> >
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