Indeed, that would make sense for filter, but since filterv immediately 
puts them all into a vector, I was particularly puzzled by the warning on 
its doc string.

In my case I am not relying on the side effects for anything, I merely 
cannot guarantee there are none (and even if chunking were an issue, the 
list is immediately fully consumed). So I tentatively think I am ok, but it 
is still an unsettling warning.

On Wednesday, September 2, 2015 at 11:06:01 AM UTC-5, Raymond Huang wrote:
>
> I believe the reason it's not recommended is because it returns a lazy 
> chunked sequence. This means that it's not guaranteed to eagerly perform 
> your side-effects, unless you wrap it in `doall`.
>
> On Wed, Sep 2, 2015 at 8:48 AM, James Elliott <brun...@gmail.com 
> <javascript:>> wrote:
>
>> I notice that the documentation for filter and filterv are emphatic that 
>> the predicate you are using be free of side effects. Why is that so? For 
>> example, I would like to use filterv to collect a list of lighting 
>> effects which respond false to a protocol method which asks whether they 
>> have finished. In the implementation of that method, the effects are free 
>> to update their internal state based on the current show state and time, 
>> when deciding whether or not they are finished, and so I can’t guarantee 
>> there will be no side effects while filtering the effects. Does that mean I 
>> can’t use filterv? If not, why not? Looking at the source, I see no 
>> obvious problems.
>>
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