@Matthew It also follows the dot notation for function composition, right?
This makes sense, but then:

(def iso8601->timestamp
  (comp date-time->timestamp iso8601->date-time))


On Fri, Oct 2, 2015 at 5:39 PM, Matthew Boston <matthew.bos...@gmail.com>
wrote:

> comp isn't backwards, it's just "outside-in".
>
> ((comp not zero?) x) == (not (zero x))
>
> So it reads in the same order from left-to-right as it would otherwise.
>
>
> On Friday, October 2, 2015 at 1:10:54 PM UTC-6, Jason Felice wrote:
>>
>> Why is it so hard to describe to new people?
>>
>> I mean, the questions I get are (I understand what's happening here, but
>> I can't describe it well):
>>
>> 1. If -> threads things first-to-last, why does the middleware run
>> last-to-first?
>> 2. Why is comp backwards?
>> 3. Wait, so how does each wrapper get a second pass at it?
>> 4. Why would you do this to me?
>>
>> I hope to write a blog or something on this, but I wanted to check in
>> here first.  Any ideas on how to talk about this?
>>
>> Thanks,
>> -Jason
>>
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