You are so right, the answer seems obvious now :)

Thanks,
Witold Szczerba

On Sat, Dec 19, 2015 at 1:57 AM, Herwig Hochleitner <hhochleit...@gmail.com>
wrote:

> Use a function instead of the loop:
>
> (defn ws [req]
>   (with-channel req channel
>     ((fn loop-f [x]
>        (timer/schedule-task
>          3000
>          (println x)
>          (loop-f (+ x 1))))
>      0)))
>
> loop-recur is used to prevent unbounded stack growth, but the timer task
> acts as a sort of trampoline anyway, resetting the stack between each
> invokation. The lazy-seq macro works in a similar way.
>
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