On Oct 05 2016, Julia Lawall <julia.law...@lip6.fr> wrote:
>>
>> 2. ..and how would I go about if instead of the type, I want to replace
>> a variable name? (my_type *ptr --> my_type *pointer).
>
> I'm not completely sure what the issue is here. Do you specifically want
> to convert ptr to pointer? Is the type important? To make exactly what
> you have written, you could put:
>
> @@
> typedef my_type;
> idexpression mytype * p1;
> @@
>
> - ptr@p1
> + pointer
>
> This checks for the word ptr, and also checks that it is an identifier of
> the right type. I haven't tested it, so let me know if there is any
> problem.
It workes somewhat... but not completely.
Here's what I wanted to do: I merged two structures (struct fuse_session
and struct fuse_ll) into one (struct fuse_session). I've first replaced
all the type names, and then manually fixed the cases where this
resulted in bogus/redundant code (typically in functions that used to
work with both structs).
Now my project compiles and runs fine, but I the variable naming is
inconsistent: in some cases the struct fuse_session pointer is called
*se (these were the variables that were always of type struct
fuse_session), and in other cases the pointer is called *f (these were
the variables that were previously of type struct fuse_ll).
I'd like to fix this too, and always refer call fuse_session pointers
"se" (except where this name is already used for something else, but
I'll just fix this up by hand afterwards). I tried the following patch:
$ cat se-name.cocci
@@
idexpression struct fuse_session *p1;
@@
- f@p1
+ se
but it resulted in these changes:
struct fuse_session *f = req->se;
- struct cuse_data *cd = f->cuse_data;
- size_t bufsize = f->bufsize;
+ struct cuse_data *cd = se->cuse_data;
+ size_t bufsize = se->bufsize;
So it seems to replace the variable where its used, but not where it's
defined.
Is there a way to catch the definitions too?
Best,
-Nikolaus
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