Try this. Here datatypes also are of concern :).
<xsl:when test="$xsldttype='number'">
<xsl:for-each select="DATALINE/*[name() = $xslcol]">
<xsl:sort select="." data-type="number"/>
<xsl:call-template name = "tablerow" />
</xsl:for-each>
</xsl:when>
<xsl:when test="$xsldttype='text'">
<xsl:for-each select="DATALINE/*[name() = $xslcol]">
<xsl:sort select="."/>
<xsl:call-template name = "tablerow" />
</xsl:for-each>
</xsl:when>
Try to search for examples on www.google.com.
Have fun,
Leonid Kleiner
----- Original Message -----
From: "Axel Honfi" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, March 27, 2002 6:22 AM
Subject: XSL-question: sort with parameter
> Hi!
>
> I passed a parameter to a stylesheet and I can get the value with
> <xsl:value-of select="$order-by"/>.
>
> But I need to sort data by the value of the parameter like
>
> <xsl:sort select="$order-by" order="ascending"/>.
>
> But with this nothing happens and all other forms I tried also failed.
>
> Does anyone know how to work this?
>
> Thanks a lot
>
> Axel
>
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