GordoRank commented on issue #18422:
URL: https://github.com/apache/echarts/issues/18422#issuecomment-2045929711
I've just come up against the same issue and have quickly modified the
source code to rectifiy it. I don't have time to make a PR right now but the
simplest solution is to modify the getMinorTicks function to the following:
` IntervalScale.prototype.getMinorTicks = function (splitNumber) {
var ticks = this.getTicks(true);
var minorTicks = [];
var extent = this.getExtent();
var largestTickInterval = null;
for (var i = 1; i < ticks.length; i++) {
var nextTick = ticks[i];
var prevTick = ticks[i - 1];
var interval = nextTick.value - prevTick.value;
if(largestTickInterval === null || interval > largestTickInterval) {
largestTickInterval = interval;
}
}
for (var i = 1; i < ticks.length; i++) {
var nextTick = ticks[i];
var prevTick = ticks[i - 1];
var count = 0;
var minorTicksGroup = [];
//var interval = nextTick.value - prevTick.value;
var interval = largestTickInterval;
var minorInterval = interval / splitNumber;
while (count < splitNumber - 1) {
var minorTick = roundNumber(prevTick.value + (count + 1) *
minorInterval);
// console.log('minortick: ' + minorTick + 'ex0: ' + extent[0] + '
ex1: ' + extent[1]);
// For the first and last interval. The count may be less than
splitNumber.
if (minorTick > extent[0] && minorTick < extent[1]) {
minorTicksGroup.push(minorTick);
}
count++;
}
minorTicks.push(minorTicksGroup);
}
return minorTicks;
};`
I'm sure there will be a more efficient way of doing it, but simply
pre-calculating the largest **full** tickInterval first and using that to
consitently calculate the minorTick distances does the trick.
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