functioner edited a comment on pull request #2727:
URL: https://github.com/apache/hadoop/pull/2727#issuecomment-788518502
> > According to the comment in that test case, it "should not time out
because effective rpc-timeout is multiple of ping interval: 1600 (= 800 * (1000
/ 800 + 1))", and it doesn't mean that it shouldn't time out.
>
> The SocketTimeoutException is thrown on `Socket#read` based on the timeout
value set by `Socket#setSoTimeout`. It is set to 800(pingInterval) in the test
because (pingInterval < rpcTimeout). The SocketTimeoutException is thrown at
800ms first time and swallowed because 800 < rpcTimeout. SocketTimeoutException
is thrown again at 1600ms then handled because 1600 > rpcTimeout.
Oh, I think the current fix I propose does not consider the case of
`rpcTimeout != 0`. It always assumes that rpcTimeout == 0, and calculate the
rpcTimeout based on pingInterval.
I'm going to propose:
```
private void handleTimeout(SocketTimeoutException e, int waiting)
throws IOException {
int timeout = 0;
if (rpcTimeout == 0) {
// effective rpc timeout is rounded up to multiple of pingInterval
// if pingInterval < rpcTimeout.
timeout = (doPing) ? pingInterval : rpcTimeout;
} else {
timeout = rpcTimeout;
}
if (shouldCloseConnection.get() || !running.get() ||
(0 < timeout && timeout <= waiting)) {
```
@iwasakims Do you agree?
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