Re: [uid]llang] Adding refactored [lang] identifiers to [uid]

[Phil Steitz]

I propose an IdentifierKit
producing IdentifierFactory's, where an IdentifierFactory produces Ids.


Or "IdentifierFactory" producing "IdentifierBuilders."
Argh!  I meant "IdentifierBuilderFactory".





---------------------------------------------------------------------
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]