Nem olhei o gabarito....hehe

Vou olhar aqui pra opinar tb.

[]s

2011/5/11 Lucian Sturião <[email protected]>

> A 4 tá errada não?
>
> Se você definir um método void *g(int x)*; numa interface, e escrever *void
> g(int x) { metodo }* na classe, dá erro de compilação.
> se fosse *public void g (int x) { método }*, compilaria e só o g estaria
> visível.
>
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-- 
Zaedy Dantas Sayão
Graduando em Ciência da Computação DCC/UFRJ
http://www.manufato.com.br/
MSN: [email protected]

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