Você deve ter definido I sendo uma classe comum.

Em 11 de maio de 2011 18:18, Augusto Vanderley
<[email protected]>escreveu:

> Eu lembro que na hora da prova testei no eclipse e compilou corretamente o
> método g(int x)
>
> Em 11 de maio de 2011 11:02, Leonardo F. Borba <[email protected]>escreveu:
>
> Lucian,
>>
>> A melhor resposta seria esta que você deu, assim como o Peter já havia
>> dito em outra thread, é necessário você declarar o método na classe como
>> public.
>>
>> Se você definir um método void *g(int x)*; numa interface, e escrever *void
>> g(int x) { metodo }* na classe, dá erro de compilação.
>> se fosse *public void g (int x) { método }*, compilaria e só o g estaria
>> visível.
>>
>> Vou comunicar ao professor.
>>
>> Abraços
>>
>> Leonardo Borba
>>
>>
>>
>> Em 11 de maio de 2011 08:32, Zaedy Sayão <[email protected]> escreveu:
>>
>> Nem olhei o gabarito....hehe
>>>
>>> Vou olhar aqui pra opinar tb.
>>>
>>> []s
>>>
>>>
>>> 2011/5/11 Lucian Sturião <[email protected]>
>>>
>>>> A 4 tá errada não?
>>>>
>>>> Se você definir um método void *g(int x)*; numa interface, e escrever *void
>>>> g(int x) { metodo }* na classe, dá erro de compilação.
>>>> se fosse *public void g (int x) { método }*, compilaria e só o g
>>>> estaria visível.
>>>>
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>>>
>>>
>>>
>>> --
>>> Zaedy Dantas Sayão
>>> Graduando em Ciência da Computação DCC/UFRJ
>>> http://www.manufato.com.br/
>>> MSN: [email protected]
>>>
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>>
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>
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