On Sun, Nov 23, 2008 at 11:02 PM, Feng, Libo <[EMAIL PROTECTED]> wrote: > > Hi, All, > > I am still trying to implement the S3 state in dbm690t. Now I can jump into > the waking vector code running under the real mode. However, the code > contains some 32bit instructions, when these instructions are executed, the > system always hangs, for the processor thought they were of 16bit. Please see > the code in the below link. > > http://lxr.linux.no/linux+v2.6.18/arch/x86_64/kernel/acpi/wakeup.S > > In 37 and 38 line, there are two 32bit instructions, > > 66 6a 00 pushl $0 # Kill any dangerous flags > 66 9d popfl > > You can see the machine codes starting with 0x66 indicating these 32bit > instructions. However, processor always thought these were of 16bit, so, > instructions are changed into: > > 66 6a push byte 00h > 00 66 9d add [bp-63h], ah >
what could explain this is that you are not in 16-bit mode, you are actually in 32-bit mode for some reason. The 66 will then run these instructions in 16 bit. That is just a guess. Are you certain you are in 16 bit mode? ron -- coreboot mailing list: [email protected] http://www.coreboot.org/mailman/listinfo/coreboot
