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On Mon, May 07, 2001 at 08:47:38AM +0200, Bodo Eing wrote:
> if the commit() is placed here, won't it be always executed, because 
> there are no die statements which stop code execution upon errors 
> before ? Shouldn't committing be made dependent of the value of $@ 
> like

There is a die statement in the sample.  Reread about what RaiseError does.

Personally I consider the fact that RaiseError is not on by default a bug.

- -- 
Stephen Clouse <[EMAIL PROTECTED]>
Senior Programmer, IQ Coordinator Project Lead
The IQ Group, Inc. <http://www.theiqgroup.com/>

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