On 22 Oct 2009, at 12:57, Kenny Guan wrote:
> Hi Pierre,
>
> thanks for your reply. Maybe I didn't describe my question clearly.
> the
> attributes of Company I want is like "founder", "year of foundation"
> etc.
>
> A more specific example, an instance of Company like, Apple, has an
> attribute "founder" with value of "Steve Jobs".
Try something like:
SELECT DISTINCT ?p WHERE {
?s a <http://dbpedia.org/ontology/Company> .
?s ?p ?o .
}
This gets all resources of type Company, then finds all triples that
have this resource as subject, and returns the predicate of these
triples. The DISTINCT removes duplicates.
Optionally you might want to also put this into the angle brackets,
after the last dot:
FILTER (REGEX(?p, 'ontology'))
This removes all properties that do not have "ontology" in the URI,
giving you only the properties defined by the ontology, and skipping
general infobox properties.
Hope that's what you're after.
Best,
Richard
>
> does this make any sense?
>
> Many thanks
> Kenny
>
>
> On Thu, Oct 22, 2009 at 4:42 PM, Pierre De Wilde <[email protected]
> >wrote:
>
>> SELECT * WHERE { {?s ?p ?o. FILTER(?s IN (<
>> http://dbpedia.org/ontology/Company>))} }
>>
>> 2009/10/22 Kenny Guan <[email protected]>
>>
>>> Hey,
>>>
>>> I am doing some work on semantic search and I may want to use
>>> dbpedia as
>>> seed data. The thing I want to do now is, given a dbpedia ontology
>>> class,
>>> say COMPANY, i want to get all attributes of COMPANY.
>>>
>>> I see there are 170+ classes and 900+ attributes in dbpedia
>>> ontology. For
>>> each object/instance, its type/class is specified in "Ontology type"
>>> dataset, its attributes are specified in "Ontology infoboxes"
>>> dataset. But
>>> seems no dataset directly specifies the attributes of a particular
>>> class,
>>> right?
>>>
>>> if it is, how to write a SPARQL script to get attributes of
>>> COMPANY? I
>>> have never written a SPARQL, hope to start with this one. can
>>> someone give
>>> some help?
>>>
>>> Thanks in advance
>>> Kenny
>>>
>>>
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