On 09/27/2016 10:05 AM, Deepak Gupta wrote:
If I remove the else part of the if-condition, it works, else the constraints
become zero. This implies, I should not try to set boundary indicator for
anything which is not at the boundary,
Correct.
which is obvious. I know it was a
mistake from my side, but I would like to know why it was a problem (what goes
on in the background as per the implementation?)
In essence you are saying that some interior face is a boundary. If you come
from each of the two adjacent cells, the interface will then look like an
external boundary (at which there can be no neighbor) and so no constraints
will be computed.
Best
W.
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Wolfgang Bangerth email: [email protected]
www: http://www.math.colostate.edu/~bangerth/
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