If I understand it correctly, that is equivalent to solving Ax = b, with A 
and b given, and x returned?

Am Montag, 15. Juli 2019 22:03:46 UTC+2 schrieb Daniel Arndt:
>
> Maxi,
>
> The interface for TimeStepping::evolve_one_time_step is:
>
> virtual double
>   evolve_one_time_step(
>   std::vector<std::function<VectorType(const double, const VectorType &)>>
>   & F,
>   std::vector<std::function<
>   VectorType(const double, const double, const VectorType &)>> &J_inverse,
>   double t,
>   double delta_t,
>   VectorType & y);
>
> and does not depend on UMFPACK at all. You just need to provide a 
> function-type object that can be used for evaluating the inverse of the 
> Jacobians and the right-hand side.
> You might also want to have a look at the test base/time_stepping_01 (
> https://github.com/dealii/dealii/blob/master/tests/base/time_stepping_01.cc
> ).
>
> Best,
> Daniel
>
>
> Am Mo., 15. Juli 2019 um 15:04 Uhr schrieb 'Maxi Miller' via deal.II User 
> Group <dea...@googlegroups.com <javascript:>>:
>
>> As far as I understand all implicit time-stepping methods in the 
>> TimeStepping-namespace take a function which invert the jacobian matrix and 
>> the mass matrix (combined). This is done using a sparse solver (UMFPACK). 
>> Is it that still possible for a larger system (10kk DoFs), or do I have to 
>> resort to other methods, after inverting the sparse matrix will result in a 
>> dense matrix (which likely will overflow my memory)?
>>
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