On 7/9/20 1:18 AM, Alex wrote:
I am new to dealii. I have a question on step-11. For a domain with a curved
boundary such as step-11 with fe(1), is the boundary element still a bilinear
one if mapping order>1? i.e. always 4 dofs on a boundary element? Thanks
You need to distinguish between the element and the mapping. The element's
shape functions are defined on the reference cell, and for a Q1 element
(=fe(1)), there are always 4 shape functions in 2d.
The *mapping* on the other hand is used to describe how shape functions are
transformed from the reference cell to the real cell. This mapping is more
complicated when you have a curved boundary than if you have a straight
boundary, but it does not affect *how many* shape functions there are.
Best
W.
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Wolfgang Bangerth email: [email protected]
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