On Fri, Dec 25, 2009 at 04:44:03PM +0100, Christian Brabandt wrote:
> A far lines later, you'll find that piece of code:
> f (!isnumber_p (u))
>     error_msg = _("invalid user");
> 
> and isnumber_p fails, because u was negative in my case.

Maybe I'm dense.  Why would isnumber_p() fail on a signed char string?



-- 
To UNSUBSCRIBE, email to [email protected]
with a subject of "unsubscribe". Trouble? Contact [email protected]

Reply via email to