Paul Johnson wrote:
William Ballard <[EMAIL PROTECTED]> writes:
On Fri, Sep 24, 2004 at 07:28:22AM -0700, Zachary Rizer wrote:

No.  Unstable (sid) will always be unstable.  Testing
becomes the new stable, and then a new testing is born
(etch?).

Could you be more precise? What is renamed, what is forked, what is cloned?


Start of the cycle:

Unstable forks a new testing.
Testing freezes, frozen replaces testing.
Frozen then replaces existing stable, which moves to the obsolete archive.



The 'new' testing will be a fork of stable[which in turn is derived from the 'old' testing], not unstable...

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