Hi, On Tue, Mar 04, 2003 at 12:15:56PM -0800, Vineet Kumar wrote: > * Nori Heikkinen <[EMAIL PROTECTED]> [20030304 12:11 PST]: > > hey, > > > > by default, a shell script just appears as the script name in a list > > of processes (ps; top), right? how can i make it show each command > > called within the script as it's being executed? > > It already is. For each program called from the script, > the shell forks and execs a new process, which shows up in the > process list. Of course, you won't see shell builtin commands > in the process list, just the shell name and script name.
But see this, I don't understand:
( ~ )$
( ~ )$ echo 'sleep 10' > test.sh
( ~ )$ chmod +x test.sh
( ~ )$ ./test.sh &
[1] 9771
( ~ )$ ps
PID TTY TIME CMD
26101 pts/3 00:00:00 bash
9771 pts/3 00:00:00 bash
9772 pts/3 00:00:00 sleep
9773 pts/3 00:00:00 ps
( ~ )$
( ~ )$
[1]+ Done ./test.sh
( ~ )$
and If I had run it in background, then on another terminal, I saw
in 'ps -A' the bash and sleep processes too.
--
+----------------------------------+
| Martin Kacerovsky |
| e-mail : wizard(AT)matfyz(DOT)cz |
| home : http://wizard.matfyz.cz |
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