On Thu, May 16, 2002 at 09:02:25AM +0200, Perceval Anichini wrote: > When you write > argv + 1, the compiler will understand : compute the address > of argv, and add one time the size of the type which is pointed by argv. > I remember to you that argv[1] = argv + 1. Brackets are only syntactic > sugar, which allows us not seeing we are dealing with pointer arithmetic.
This could hardly be more offtopic, but argv [1] == *(argv + 1) not (argv + 1). &(argv [2]), or argv + 2, would have been what the original coder was trying to express. Cheers, --Pete -- To UNSUBSCRIBE, email to [EMAIL PROTECTED] with a subject of "unsubscribe". Trouble? Contact [EMAIL PROTECTED]