Re: bash question: reporting a variable named within a variable

[Colin Watson]

On Fri, Apr 04, 2003 at 12:34:33AM +0100, Colin Watson wrote:
> On Thu, Apr 03, 2003 at 01:58:35PM -0800, Corey Hickey wrote:
> > #!/bin/bash
> > 
> > FOO=bar
> > BLAH=blarg
> > 
> > for var in FOO BLAH ; do
> >     echo $var = $"$var" #this part is messed up
> > done
> 
> Try this, which I believe to be the best way:
> 
>   echo '$var = ' `eval 'echo "$foo"'`

Make that:

  echo "$var = " `eval 'echo "$foo"'`

-- 
Colin Watson                                  [EMAIL PROTECTED]


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