Am Sam, 2003-06-28 um 16.03 schrieb David selby: > Hello, > > I am writing bash a bash & sed script, it has been going suprisingly > well. I need a loop to count 9 times & the variable n to the count .. > > for n=1 to 9 > .... > next > > kind of thing, but this is not BASIC !! > > My best guess is > > declare -i n=1 > while [ $n < 9 ]; do > ..... > n=$((n+=1)) > done >
I guess n=$((n+=1) is wrong, try
let n=$n+1
instead.
> All i get is ...
>
> [EMAIL PROTECTED]:/usr/local/myfiles/dave/websites/kcards$ ./gensite
> ./gensite: 9: No such file or directory
>
> I have defined it as an integer, used the less than operator for
> integers, ... errr ... I know its something stupid but I can't crack it ....
A simple
n=1
instead of the "declare" does the trick, too.
> PS is there a more ellagent way to do a counted loop as well as a way
> that works ?
I *personally* would do it like this (tested):
n=0
while test "$n" -ne 9
do
let n=$n+1
echo "$n"
done
HTH
--
Matthias Hentges
Cologne / Germany
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