Hi, maybe something like this: PORT=8079;for i in $(find . -iname "server.xml"|sort); do let PORT=$PORT+1; echo $PORT > $i; done
or this: PORT=8079;for i in $(find . -iname "server.xml"|sort); do let PORT=$PORT+1; sed -i -e "s/actualPort/$PORT/g" $i; done best regards. 2010/11/26 Kaushal Shriyan <kaushalshri...@gmail.com> > Hi, > > In my home folder I have 6 tomcat directories under > /home/kaushal/tomcat0......6 > > Under each of these tomcats there are sub folder conf and inside these conf > there is a file by the name server.xml so for example I have > tomcat0,tomcat1,tomcat2,tomcat3,tomcat4,tomcat5 so i need to edit server.xml > and set port numbers for tomcat0 to 8080 tomcat1 to 8081 and similarly for > others,the other way is to go to individual directory and do it > > Please suggest/guide > > Thanks and Regards > > Kaushal > <http://int.ask.com/web?siteid=10000861&webqsrc=999&l=dis&q=8888>
