On 12/31/2012 12:33 PM, Zbigniew Komarnicki wrote:
Is this OK or is this a bug, when the wariable 'n' is
initializing by negative value? There no any warning.
Is this normal? I know that value -5 is converted
to unsigned but probably this should by printed a warning,
when this is a constant value. What do you think about this?
// prog.cpp
#include <iostream>
using namespace std;
int main()
{
const unsigned int n = -5;
cout << "The variable n is: " << n << endl;
return 0;
}
Results:
$ g++ -Wall -W prog.cpp -o prog
$ ./prog
The variable n is: 4294967291
Thank you.
I do not believe this is an issue. The warning is probably just telling
you that you tried to initialize a constant unsigned int with a signed
value. I don't know if the compiler converts it to 5 or it converts it
to the unsigned value that takes form where -5 would take in a signed
value. I suggest experimenting with that to make sure that any important
behavior dependent on the value works properly. Thought o be honest if
they were planning on using a negative value for something important
they should have left the variable signed.
Yaro
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