On Fri, Dec 01, 2000 at 08:44:26AM -0500, Raul Miller wrote: > On Fri, Dec 01, 2000 at 06:54:32AM -0500, Raul Miller wrote: > > > > > However, with the 3:1 supermajority which affects A, you get: > > > > > 10 : 0 B:C > > > > > 3 1/3: 0 A:B > > > > > 3 1/3: 0 A:C > > > > > B wins. > Mechanism.. how do I explain that I'm talking about the > mechanism itself..?
I'm not sure what you're talking about because in the above, A wins. (It's the Condorcet winner, so all Condorcet methods select it) Whatever method you're applying, you've either got a bad description of it, or you're doing something wrong. (Any method that declares B the winner is obviously broken beyond repair; but Condorcet methods don't do that) Cheers, aj -- Anthony Towns <[EMAIL PROTECTED]> <http://azure.humbug.org.au/~aj/> I don't speak for anyone save myself. GPG signed mail preferred. ``Thanks to all avid pokers out there'' -- linux.conf.au, 17-20 January 2001
