Hello Leo! AT> From: Anton Tagunov [mailto:[EMAIL PROTECTED] AT> AT> In fact if we have dependency AT> AT> A - > B AT> AT> but A has inline activation and B - background, A will AT> still be (probably?) initialized before B.
LS> Doesn't that mean that B will be initialized as a part of A's LS> init, as lazy init kicks in? 1) Don't think so. If I understand the code correctly then if A has activation policy 'inline' and B - 'background' then when A is initialized the handler for B won't be prepared yet, will it? 2) errr.. I seem to find I probably do not understand the code sufficiently.. ThreadSafeComponentHandler does need preparation, does not it? But then how does the lazy initialization work at all? -Anton --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
