in ruby:
def token(nodes) 1.upto(nodes) {|i| p (2**127/nodes) * i}; end
>> token(3)
56713727820156410577229101238628035242
113427455640312821154458202477256070484
170141183460469231731687303715884105726
On Thu, Jun 17, 2010 at 12:08 PM, Lev Stesin <lev.ste...@gmail.com> wrote:
> Hi,
>
> What is the correct procedure to create a well balanced cluster (in
> terms of key distribution). From what I understand whenever I add a
> new node its takes half from its neighbor. How can I make each node to
> contain 1/3 of the keys in a 3 node cluster? Thanks.
>
> --
> Lev
>
