so bc and ruby agree ;)
On Thu, Jun 17, 2010 at 10:20 PM, Benjamin Black <b...@b3k.us> wrote:
> in ruby:
>
> def token(nodes) 1.upto(nodes) {|i| p (2**127/nodes) * i}; end
>
> >> token(3)
> 56713727820156410577229101238628035242
> 113427455640312821154458202477256070484
> 170141183460469231731687303715884105726
>
>
> On Thu, Jun 17, 2010 at 12:08 PM, Lev Stesin <lev.ste...@gmail.com> wrote:
> > Hi,
> >
> > What is the correct procedure to create a well balanced cluster (in
> > terms of key distribution). From what I understand whenever I add a
> > new node its takes half from its neighbor. How can I make each node to
> > contain 1/3 of the keys in a 3 node cluster? Thanks.
> >
> > --
> > Lev
> >
>
