Hi Armin,
Armin Le Grand schrieb:
Regina Henschel schrieb:
Hi Armin,
Armin Le Grand schrieb:
Regina Henschel schrieb:
...
Take a line
A line is unfortunately a bad example; it does not really get
transformed from the tought unit line from (0,0) to (1,0), but
internally creates a two-point polygon with the points where they belong
and no transformation at all. Could You use a rectangle as example,
please? This will make things more reliable to reproduce.
The transformation for a rectangle implies to be applied to a unit
rectangle from (0,0) to (1,1), thus completely defining position, size,
rotation and shear of the shape. The order is:
M = MTranslate * MRotate * MShearX * MScale
? I have expected a equation
M = MTranslatePos * MTranslateCenter * MRotate * MShearX * (inverse
MTranslateCenter) * MScale
with MTranslateCenter with dx=ScaleX/2 and dy=ScaleY/2, because rotation
and shearing are done on the center point of an object and the rotation
matrix is usually defined for rotating around origin and shearing matrix
is defined for fix x-axis.
Of cause it is possible to use one translation, but the values are not
simple, because translation is not commutative with rotation or shearing.
of course multiplied from right to left as usual in matrix notation.
Take a classic rectangle at position (-1cm|-1cm) and
width=2cm|height=2cm. Set a slant angle of 20 degrees via dialog.
The matrix is
2001 728.304 -636
0 2001 -1001
0 0 1
Applying the matrix to (0|0) and (1|1) results in
/ \ / \ / \
| 2001 728.304 -636 | | 0 | | -636 |
| 0 2001 -1001 | * | 0 | = | -1001 |
| 0 0 1 | | 1 | | 1 |
\ / \ / \ /
/ \ / \ / \
| 2001 728.304 -636 | | 1 | | 2093.304 |
| 0 2001 -1001 | * | 1 | = | 1001 |
| 0 0 1 | | 1 | | 1 |
\ / \ / \ /
The coordinates on screen are (-0.64cm|-1cm) and (0.64cm|1cm).
The matrix is wrong for the rectangle too.
Creating the matrices manually on paper (without rotation) as described
above, results in (besides the +1 in width and height) :
2000 -727.94 -636.03
0 2000 -1000
0 0 1
which would give the correct coordinates.
I also need to know on which level You get the matrix: From ODF
FileFormat, from UNO API or from SdrObject level? This is not always the
same, unfortunately...
I get it from UNO API. I use a Basic macro, where I get the selected
shape, set a breakpoint and look at the shape with the "watch" tool.
If I save the file and unpack it, the rectangle has
<draw:rect draw:style-name="gr1" draw:text-style-name="P1"
draw:layer="layout" svg:width="2cm" svg:height="2cm"
draw:transform="skewX (0.3490658503988) translate (-0.636cm -1cm)">
There is no matrix.
Kind regards
Regina
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