If you really want to get technical (ie a proper OO language) then it's
not necessarily if the function has a different number of arguments.

Ie in Java you can say

public void myFunction(String s) {
 // do something
}

public void myFunction(Object o) {
 // do something else
}

public void myFunction() {
 // do something else again
}

public void myFunction(String s, Object o) {
 // do something else again
}

Basically the function is different because of the arguments, not the
amount, but the type.

HTH (although probably more than you needed!)

Paul

Paul Johnston
Technical Architect
PJ Net Solutions Ltd
http://www.pjnetsolutions.com
+44 (0)7866 573013


> -----Original Message-----
> From: Aidan Whitehall [mailto:[EMAIL PROTECTED]]
> Sent: Friday, November 29, 2002 2:07 PM
> To: [EMAIL PROTECTED]
> Subject: RE: [ cf-dev ] for loops...
>
>
> > you've got two functions with the same name, but different
> amount of
> > arguments.  so if you call function(arg1), it'll do the
> function that
> > accepts 1 argument.  if you call function(arg1, arg2), it'll do the
> > function that takes 2 arguments.  very useful.
>
> Ahh... I see. Thanks.
>
>
> --
> Aidan Whitehall <[EMAIL PROTECTED]>
> Macromedia ColdFusion Developer
> Fairbanks Environmental +44 (0)1695 51775
>
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