That should be
function create()
{
name = "default"
create(name)
}
Justin
>
> function create()
> {
>
> name = "default"
> create(default)
> }
>
> function create(string name )
> {
> new thing called name
> }
>
>
>
>
> Justin
>
> > -----Original Message-----
> > From: Paul Johnston [mailto:[EMAIL PROTECTED]]
> > Sent: 29 November 2002 14:24
> > To: [EMAIL PROTECTED]
> > Subject: RE: [ cf-dev ] for loops...
> >
> >
> > If you really want to get technical (ie a proper OO language) then it's
> > not necessarily if the function has a different number of arguments.
> >
> > Ie in Java you can say
> >
> > public void myFunction(String s) {
> > // do something
> > }
> >
> > public void myFunction(Object o) {
> > // do something else
> > }
> >
> > public void myFunction() {
> > // do something else again
> > }
> >
> > public void myFunction(String s, Object o) {
> > // do something else again
> > }
> >
> > Basically the function is different because of the arguments, not the
> > amount, but the type.
> >
> > HTH (although probably more than you needed!)
> >
> > Paul
> >
> > Paul Johnston
> > Technical Architect
> > PJ Net Solutions Ltd
> > http://www.pjnetsolutions.com
> > +44 (0)7866 573013
> >
> >
> > > -----Original Message-----
> > > From: Aidan Whitehall [mailto:[EMAIL PROTECTED]]
> > > Sent: Friday, November 29, 2002 2:07 PM
> > > To: [EMAIL PROTECTED]
> > > Subject: RE: [ cf-dev ] for loops...
> > >
> > >
> > > > you've got two functions with the same name, but different
> > > amount of
> > > > arguments. so if you call function(arg1), it'll do the
> > > function that
> > > > accepts 1 argument. if you call function(arg1, arg2), it'll do the
> > > > function that takes 2 arguments. very useful.
> > >
> > > Ahh... I see. Thanks.
> > >
> > >
> > > --
> > > Aidan Whitehall <[EMAIL PROTECTED]>
> > > Macromedia ColdFusion Developer
> > > Fairbanks Environmental +44 (0)1695 51775
> > >
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> > >
> >
> >
> >
> >
> >
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