how do I find the name of the target?
Dave

On Sat, May 28, 2016 at 4:46 PM, Sterling Hughes <[email protected]> wrote:
> $ newt run my_blinky_sim
>
> Just the name of the target, don’t provide the binary path.  All of the
> commands run based on the name of the target.
>
> We’ll update the documentation here:
> http://mynewt.apache.org/os/get_started/project_create/
>
> to use newt run.  It was written prior to the Docker image being supported,
> and works with the native toolset.
>
> Newt run is documented here:
> http://mynewt.apache.org/newt/command_list/newt_run/, albeit it should
> probably have better documentation for simulated targets.
>
> Sterling
>
> On 28 May 2016, at 16:18, David Moshal wrote:
>
>> ```
>> ⇒  ../newt run ./bin/my_blinky_sim/apps/blinky/blinky 0
>> Error: Invalid target name: ./bin/my_blinky_sim/apps/blinky/blinky
>> ```
>>
>> Undocumented cryptic commands required for 'getting started' project ?
>> Not good, and doesn't inspire newbies to donate their time to the
>> project, just saying.
>>
>> For reference: it took me 5 mins from zero to blinky light on the mBed
>> platform, which seems like a reasonable alternative to MyNewt, best as
>> I can tell, so there's room for improvement if you want to grow the
>> platform.
>>
>> David
>>
>>
>>
>> On Sat, May 28, 2016 at 3:48 PM, Christopher Collins
>> <[email protected]> wrote:
>>>
>>> On Sat, May 28, 2016 at 01:38:48PM -0700, Sterling Hughes wrote:
>>>>
>>>> $ newt run <target-name>
>>>>
>>>> Will do this for you.  No need to call binary directly.
>>>
>>>
>>> If you are building for real hardware (i.e., not sim), then you need to
>>> add a version number to the end of the command.  So, the command would
>>> look something like this:
>>>
>>>     newt run myblinky 0
>>>
>>> If you leave off the 0, you will get a cryptic and intimidating error
>>> message.
>>>
>>> I was thinking we might want to make the version number optional.  When
>>> people use the run command, most of the time they probably don't care
>>> what version number the produced image has.
>>>
>>> Chris

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