Hi Joe,

On Mon, 2007-05-21 at 12:36 -0400, Joe Smith wrote:
> Eike Rathke wrote:

> > The GNU libstdc++ code won't do anyway because it is GPL, not LGPL. ...
> 
> IANAL--I don't even like to discuss licenses--but I thought as long as 
> you simply _use_ a GPL library, you're not under the GPL. 

That depends largely on what you mean by "simply use a GPL library". :-)

> The idea here 
> would be to simply link to standard functions in libstdc++, not to copy 
> source code and modify it for OOo. Unless I'm mistaken, OOo already 
> links to libstdc++. At least libstdc++ is mapped in by OOo; I assume 
> that's just normal library linkage.

libstdc++ has a special license that allows run-time use by a non-GPLed
program.  It's mentioned here:

http://gcc.gnu.org/onlinedocs/libstdc++/17_intro/license.html

IANAL, but my understanding is that even a closed-source application is
allowed to (statically or dynamically) link to libstdc++ without
releasing the resulting executable under the GPL _because of this
runtime exception clause_.  But this is a special case that only applies
to libstdc++.

Kohei


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