On Apr 26, 2012, at 4:04 PM, Ben Pfaff wrote:

> +The provided bytes will be padded on the right by enough bytes with
> +value 0 to make the total number 6 more than a multiple of 8.

I think it might help to provide a brief explanation of why that happens.  How 
about something like the following?

        "Due to the way the note action is structured, the provided bytes…"

--Justin


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