An hour ago, Neil Van Dyke wrote:
> Eli Barzilay wrote at 04/22/2011 05:09 PM:
> > One way to make it fast is to have it bound to a macro so (member
> > f l eq?) expands to a `memq', and when used as a function have it
> > dispatch to `memq' if given `eq?'.
>
> If someone really wanted to do that optimization in a macro (at
> first glance, seems a little unSchemely to me, [...]
You're missing the rest of it, where I said that using it as an
expression expands to a function value as you'd expect.
--
((lambda (x) (x x)) (lambda (x) (x x))) Eli Barzilay:
http://barzilay.org/ Maze is Life!
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