Hi, I am currently using a locally build of IS Server from the latest code.When i try to get a OAuth Access token via a curl execution i am getting an error.
Curl Format used : *curl**<SPACE>**-k**<SPACE>**-d**<SPACE>* > *"grant_type=password&username=userNamepasswork&=**passWord* > *&tenantDomain=carbon.super"**<SPACE>**-H**<SPACE>**"Authorization:Basic* > *<SPACE>**Base 64 encoded clientID:clientSecret,**<SPACE>**Content-Type:* > *<SPACE>**application/x-www-form-urlencoded"**<SPACE>**https://localhost:9443/oauth2/token > <https://localhost:9443/oauth2/token>* Actual command : curl -k -d > "grant_type=password&username=xxxxx&password=xxxxx&tenantDomain=carbon.super" > -H "Authorization: Basic xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx, > Content-Type: application/x-www-form-urlencoded" > https://localhost:9443/oauth2/token Error : "Error decoding authorization header. Space delimited \"<authMethod> > <base64Hash>\" format violated." Is there is a issue with the curl command i am using here ? Thanks and Regards. Kamidu Sachith Punchihewa *Software Engineer* WSO2, Inc. lean . enterprise . middleware Mobile : +94 (0) 770566749 <%2B94%20%280%29%20773%20451194> Disclaimer: This communication may contain privileged or other confidential information and is intended exclusively for the addressee/s. If you are not the intended recipient/s, or believe that you may have received this communication in error, please reply to the sender indicating that fact and delete the copy you received and in addition, you should not print, copy, retransmit, disseminate, or otherwise use the information contained in this communication. Internet communications cannot be guaranteed to be timely, secure, error or virus-free. The sender does not accept liability for any errors or omissions.
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