[development-axapta] Re: Get next NumberSequence by code - To Tobias

[Harish Mohanbabu]

Hi Tobias,

I have set up a Number sequence 'Cust_03' as continous one. However, 
when I ran this job, I got the following error message -

------------------------------------------------------
System does not support setup 'continuous' of number 
sequence 'Cust_03'.

Number selection is cancelled.

------------------------------------------------------

What could be wrong here? Kindly advice.

Regards,

Harish

-- In [EMAIL PROTECTED], "Andrae, Tobias" 
<[EMAIL PROTECTED]> wrote:
hey - that's a joke, isn't it??
 
There is a class called NumberSeq that provides you with a valid 
number from a Number sequence. The easiest way to use it:
 
void xyz ()
{
    NumberSeq numberSeq;
    Voucher     voucher;
    ;
 
    numberSeq      = NumberSeq::newGetNumFromCode
("NameOfNumberSequence"); // fill in your wanted number sequence
    voucher        = numberSeq.num();
 
}
 
that's it - no messin' around with tables and formats......
 
best regards,
Tobias

      -----Ursprüngliche Nachricht-----
      Von: johnn_16 [mailto:[EMAIL PROTECTED] 
      Gesendet: Mittwoch, 29. Oktober 2003 16:56
      An: [EMAIL PROTECTED]
      Betreff: [development-axapta] Get next NumberSequence by 
code.
      
      
      Hi, I would like to create a new line in a table that need 
to have a 
      ParmId.  The ParmId isn't a default value so I must set it 
by code. I 
      would like to know if there is a easy way to do that or if I 
must to 
      do it manualy.  
      
      If I must do it manualy, is there something special to 
know?  Here's 
      what I'll do. I'll need to get the NumberSequence format and 
the next 
      value.  I'll merge those two values to get the formated 
      NumberSequence and I'll increment the next value in the 
      NumberSequenceTable.  Is there something else to do?
      
      Any help will be appreciate. 
      Thanks!
      
      
      
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