Kendy Kutzner wrote:
On 2003-12-03T03:24:35-0800, Martin Stone Davis wrote:Yes, that's it. Sorry, you aren't the only one who was confused.
There's a problem with the current method of calculating the estimators of binary variables using exponential decay. The problem is this: If a binary variable has a true average value near 0 or 1, the exponential decay function will frequently compute the estimate WAY off from its "true" value.
I agree.
Let DDRA = the decaying decaying running average Let decayingDecayFactor=decayFactor * MIN(DRA,1-DRA) Then compute the new decaying decaying running average as: DDRA := DDRA*(1-decayingDecayFactor) + [1 or 0]*decayingDecayFactor
Not sure if I understood correctly (is DRA==DDRA?). I will try in my words:
Given decayFactor DF (from Configfile, alchemy, whatever); two variables: DDF and DDRA;
update_ddra(value) { DDF = DF * min(DDRA, 1-DDRA); DDRA = DDRA*(1-DDF) + value*DDF; }
True. I'll make sure to guard against that when I code it today.
One problem I see is you have to make _very_ sure that DDF is never zero and DDRA never goes to exactly zero or exactly one (due to floating point rounding). If they ever do, they will stay there forever.
Well, IF the variable truly acts like a random Bernoulli variable, then I doubt it's necessary to memorize the last N values.Whatcha think?
Interesting. But I'm not sure whether your function for DDF is the best one. Further I'm not sure whether the problem at hand (average a bernoulli distribution) has a good solution without memorizing the last N values.
However, if it does something like this (for example): 1 1 0 0 0 0 1 1 0 0 1 1 1 1 0 0, where every other value really depends on the prior value, then some kind of pattern-recognition algorithm could figure that out and allow us to make better predictions. We human beings should look at the pattern of failures/successes for each binary variable we use in the estimator to see that my assumption of a random Bernoulli is a good one.
Kendy
-Martin
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