On May 1, 2009, at 3:46 PM, Evan Daniel wrote:

> Yes, that's a question worth considering.  There are both performance
> and security issues involved, I think.  Note that the partition could
> be a set of contiguous regions (allowing performance optimization
> around which piece of the keyspace you send info about), but it could
> just as easily be determined by a hash function instead.
>
> You still check the same number of filters overall -- one per peer.
> The difference is that for some peers you may have a partial filter
> set, and therefore sometimes check their filters, instead of deciding
> you don't have the memory for that peer's filter and never checking
> it.

Maybe if we partition it we can also get a free datastore histogram on  
the stats page.

--
Robert Hailey

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