Taking an address creates a function pointer, which loses the argument names. (Doesn't it?)
unfortunatly yes, but it works as a struct or class initializer https://dpaste.dzfl.pl/6aad852aea90
ArturG via Digitalmars-d-announce Sat, 11 Jun 2016 09:36:27 -0700
Taking an address creates a function pointer, which loses the argument names. (Doesn't it?)
unfortunatly yes, but it works as a struct or class initializer https://dpaste.dzfl.pl/6aad852aea90