Andrei Alexandrescu <> changed:

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--- Comment #9 from Andrei Alexandrescu <> 2010-07-22 
15:07:02 PDT ---
It looks like we're already in good shape to meet such a need. If popping
elements from the tail is needed, take(retro(range), n) should do. If getting
the last n elements from a range in the same order is needed,
range[range.length - n .. range.length] should do. I'll keep this open for a
bit more if something new shows up.

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