http://d.puremagic.com/issues/show_bug.cgi?id=9272



--- Comment #6 from Nicolas Sicard <[email protected]> 2013-01-06 04:49:57 PST 
---
(In reply to comment #5)
> (In reply to comment #2)
> > This works, where opDispatch does not take precedence:
> > ---
> > struct Foo {
> >     void opDispatch(string s)() {}
> > }
> > 
> > void baz(Foo f) {}
> > 
> > unittest {
> >     Foo foo;
> >     foo.baz();     // OK
> > }
> 
> Except, of course, opDispatch *does* take precedence here. Try this instead:
> 
> import std.stdio : writeln;
> 
> struct Foo {
>     void opDispatch(string s)() { writeln("opDispatch: ", s); }
> }
> 
> void baz(Foo f) { writeln("function: baz"); }
> 
> void main( ) {
>     Foo foo;
>     foo.baz();     // OK
> }
> 
> I can assure you it prints opDispatch: baz.

Ah! I was trapped by the minimalism of my example. OK thanks.

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