On Mon, 06 Apr 2009 08:36:18 -0400, Don <nos...@nospam.com> wrote:
Sam Hu wrote:
Thank you!
Anothe silly question then:What's the disadvantage to have the built-in
type of i-type?
Regards,
Sam
It's a very nasty type. It supports *, but isn't closed under *.
Which is really annoying for generic programming.
idouble x = 2i;
x *= x; // oops, this isn't imaginary. (BTW this currently compiles :o).
This may be a dumb question, but aren't all real numbers also technically
imaginary numbers with a 0i term? that is, I would expect the above to
evaluate to:
-4 + 0i
Which I would view as an imaginary number. Am I completely wrong here?
That being said, I hope I never have to deal with imaginary numbers in my
career, I had enough of them in school ;) So I don't really care whether
it's a builtin or not.
-Steve
