Re: how to skip the next (n) item & continue from (n+1) with a range ? e.g. in File(fn).byLine();

[mw via Digitalmars-d-learn]

On Monday, 22 June 2020 at 20:00:50 UTC, Steven Schveighoffer 
wrote:
I wouldn't recommend it, instead do a while loop:

auto range = File(fn).byLine;
while(!range.empty)
{
   auto line = range.front;
   if(someCond(line)) {
        range.popFrontN(n);
   } else {
        regularProcess(line);
        range.popFront;
   }
}

Thanks.

so `front` is peek, and `popFront` is the pop action whose return 
type is `void`, why we need two *separate* calls instead of just 
let `popFront` return T (or do we have another function for 
this)? i.e if the user forget `popFront`, it will prone to 
infinite loop bug?