Re: how to skip the next (n) item & continue from (n+1) with a range ? e.g. in File(fn).byLine();

[mw via Digitalmars-d-learn]

On Monday, 22 June 2020 at 21:27:12 UTC, Steven Schveighoffer 
wrote:
    auto line = range.front;
    range.popFront;  // pop immediately

This is a bad idea, once you popFront, the original front is 
possibly invalid (and technically is the case for byLine).

In this case, it's caused by underlying structure may reuse the 
`byLine` buffer, but I'm asking a more general question about 
range interface: why not provide an extra popAndReturnFront(), 
and the user to choose in the actual usage scenario.