Re: Can I output strings using core.stdc.stdio?

[Godnyx via Digitalmars-d-learn]

On Wednesday, 23 December 2020 at 09:50:03 UTC, Ali Çehreli wrote:
On 12/23/20 1:06 AM, Godnyx wrote:
>      for (ulong i = 0; i < args.length; i++) {
>          if (typeof(args[i]).stringof == "string")
>              printf("%s\n", args[i].toStringz);
>      }

I replaced for with foreach and it worked (and I passed 
"prompt"). static foreach would work as well.

import core.stdc.stdio : printf;
import std.string : toStringz;

void put(A...)(string prompt, A args) {
    foreach (arg; args) {
        if (typeof(arg).stringof == "string")
            printf("%s\n", arg.toStringz);
    }
}

void main() {
    string h = "World!";
    string w = "World!";
    put("prompt", h, w);
}

But it can get better: you don't want to compare typeof with 
"string" at run time. Instead, there shouldn't be any code 
generated for the non-string cases. Enter 'static if' and the 
'is' expression to feel better. :)

import core.stdc.stdio : printf;
import std.string : toStringz;

void put(A...)(string prompt, A args) {
  static foreach (arg; args) {
    static if (is (typeof(arg) == string)) {
      printf("%s\n", arg.toStringz);
    }
  }
}

void main() {
  string h = "World!";
  string w = "World!";
  put("prompt", h, w);
}

Ali

Probably the best solution! It also let's me use types other than 
string! Example: put("Prompt:", "Hello, my age is: ", 19, true); 
tho still I can't print anything. This is the code:

void put(A...)(string prompt, A args) {
    static foreach (ulong i; 0..args.length) {
        static if (is(typeof(arg) == string))
            printf("%s\n", args[i].toStringz);
        static if (is(typeof(arg) == int))
            printf("%i\n", args[i]);
        static if (is(typeof(arg) == bool)) {
            if (arg)
                printf("true");
            else
                printf("false");
        }
    }
}

void main() {
    put("Prompt:", "Hello, my age is: ", 19, true);
}

Any ideas?